Postulate 2 Postulate 5 Theorem 1 Theorem 2 Theorem 3, involution Postulate 3, commutative Theorem 4, associative Postulate 4, distributive Theorem 5, DeMorgan Theorem 6, absorption | x + 0 = x x + x’ = 1 x + x = x x + 1 = 1 (x’)’ = x x + y = y + x x + (y + z) = (x + y) + z x (y + z) = xy + xz (x + y)’ = x’y’ x + xy = x | x . 1 = x x . x’ = 0 x . x = x x . 0 = 0
xy =yx x(yz) = (xy)z x + yz = (x + y)(x + z) (xy)’ = x’ + y’ x(x + y) = x |
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